Matematika

Pertanyaan

turunan f(x)=tg(2sin2xcos2x)

1 Jawaban

  • f(x) = tg(2sin2xcos2x)
    f(x) = tg(sin4x)

    f'(x) = sec^2(sin4x) × cos4x × 4
    f'(x) = 4cos4x × sec^2(sin4x)

Pertanyaan Lainnya