Jawab nomer 7 dan 8 ya, pake caranya

√13²-(3+2)²
√13²-5²
√169-25
√144=12

7. Persekutuan dalam
[tex] KL^{2} [/tex] = [tex] 13^{2}- (3+2)^{2} [/tex]
[tex] KL^{2} [/tex] = 169 - 25
[tex] KL^{2} [/tex] = 144
KL = 12 Cm

8. Jari-jari lingkaran
a = 24
b = 32
c = 40
S = 1/2 (24 + 32 + 40)
S = 48

Luas Segitiga :
[tex] L^{2} [/tex] = 48(48 - 24)(48 - 32)(48 - 40)
[tex] L^{2} [/tex] = 48(24)(16)(8)
[tex] L^{2} [/tex] = 147456
L = 384

Jari-jari :
r = (24 x 32 x 40) / (4 x 384)
r = 30720 / 1536
r = 20 cm