tolong ya no 1 - 6......
Matematika
maulidatuladzim
Pertanyaan
tolong ya no 1 - 6......
2 Jawaban
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1. Jawaban zalkamila
1. 9/6 × 2400 = 9 × 4 = 3.600 (C)
2. 12/9 × 80/x = (dikali silang)
-> 12x = 9 × 80
-> 12x = 720
-> x = 720 ÷ 12
-> x = 60 (C)
3. 16/80 × 3/x = (dikali silang)
-> 16x = 80 × 3
-> 16x = 240
-> x = 240 ÷ 16
-> x = 15 (B)
4. 3.520/6.820 × 16/x = (dikali silang)
-> 3.520x = 6.820 × 16
-> 3.520x = 109.120
-> x = 109.120 ÷ 3.520
-> x = 31 (B)
5. 8/3 × 40/x = (dikali silang)
-> 8x = 3 × 40
-> 8x = 120
-> x = 120 ÷ 8
-> x = 15 (jumlah burung kenari)
Ditanya : jumlah burung kenari dan jalak?
Jadi, jumlah burung kenari + burung jalak
= 15 + 40
= 55 (C)
6. 6/54 x 1/2/x = (dikali silang)
-> 6x = 54 × 1/2
-> 6x = 27
-> x = 27 ÷ 6
-> x = 4.5 (C)
Semoga membantu :)) -
2. Jawaban stefanigifta
1. = (2400/6) x 9
= 400 x 9
= 3600
= C
2. 12/9 = 80/n
4/3 = 80/n
n = (80 x 3)/4
n = 240/4
n = 60
= C
3. 16/80 = 3/n
1/5 = 3/n
n = 3 x 5
n = 15
= B
4. 3520/6820 = 16/n
352/682 = 16/n
n = (16 x 682)/352
n = 31
= B
5. Kenari : Jalak = 3 : 8
Total burung = 11/8 x 40 = 440/8 = 55
= C
6. 54/6 = 0,5/n
9 = 0,5/n
n = 9 x 0,5
n = 4,5 liter
= C
Jadikan terbaik ya, thanks