Matematika

Pertanyaan

tolong ya no 1 - 6......
tolong ya no 1 - 6......

2 Jawaban

  • 1. 9/6 × 2400 = 9 × 4 = 3.600 (C)

    2. 12/9 × 80/x = (dikali silang)
    -> 12x = 9 × 80
    -> 12x = 720
    -> x = 720 ÷ 12
    -> x = 60 (C)

    3. 16/80 × 3/x = (dikali silang)
    -> 16x = 80 × 3
    -> 16x = 240
    -> x = 240 ÷ 16
    -> x = 15 (B)

    4. 3.520/6.820 × 16/x = (dikali silang)
    -> 3.520x = 6.820 × 16
    -> 3.520x = 109.120
    -> x = 109.120 ÷ 3.520
    -> x = 31 (B)

    5. 8/3 × 40/x = (dikali silang)
    -> 8x = 3 × 40
    -> 8x = 120
    -> x = 120 ÷ 8
    -> x = 15 (jumlah burung kenari)

    Ditanya : jumlah burung kenari dan jalak?
    Jadi, jumlah burung kenari + burung jalak
    = 15 + 40
    = 55 (C)

    6. 6/54 x 1/2/x = (dikali silang)
    -> 6x = 54 × 1/2
    -> 6x = 27
    -> x = 27 ÷ 6
    -> x = 4.5 (C)

    Semoga membantu :))
  • 1. = (2400/6) x 9
    = 400 x 9
    = 3600
    = C

    2. 12/9 = 80/n
    4/3 = 80/n
    n = (80 x 3)/4
    n = 240/4
    n = 60 
    = C

    3. 16/80 = 3/n
    1/5 = 3/n
    n = 3 x 5
    n = 15
    = B

    4. 3520/6820 = 16/n
    352/682 = 16/n
    n = (16 x 682)/352
    n = 31
    = B

    5. Kenari : Jalak = 3 : 8
    Total burung = 11/8 x 40 = 440/8 = 55
    = C

    6. 54/6 = 0,5/n
    9 = 0,5/n
    n = 9 x 0,5
    n = 4,5 liter
    = C

    Jadikan terbaik ya, thanks