tentukan persamaan garis yang melalui titik (1,4) dan memenuhi syarat berikut ini a. (3,-6) b. (-3,-6)

Rumus mencari persamaan garis melalui dua titik:
[tex] \frac{y- y_{1} }{y_{2}- y_{1} } = \frac{x- x_{1} }{x_{2}- x_{1} }[/tex]

a) [tex] (x_{1}, y_{1})[/tex] = (1,4) dan [tex] (x_{2}, y_{2})[/tex] = (3,-6)
[tex] \frac{y- y_{1} }{y_{2}- y_{1} } = \frac{x- x_{1} }{x_{2}- x_{1} }[/tex]
[tex] \frac{y- 4 }{-6- 4 } = \frac{x- 1 }{3- 1}[/tex]
[tex] \frac{y- 4 }{-10 } = \frac{x- 1 }{2}[/tex]
2(y - 4) = -10 (x - 1)
2y - 8 = -10x + 10
2y = -10x + 18
y = -5x + 9

b) [tex] (x_{1}, y_{1})[/tex] = (1,4) dan [tex] (x_{2}, y_{2})[/tex] = (-3,-6)
[tex] \frac{y- y_{1} }{y_{2}- y_{1} } = \frac{x- x_{1} }{x_{2}- x_{1} }[/tex]
[tex] \frac{y- 4 }{-6- 4 } = \frac{x- 1 }{-3- 1}[/tex]
[tex] \frac{y- 4 }{-10 } = \frac{x- 1 }{-4}[/tex]
-4(y - 4) = -10 (x - 1)
-4y + 16 = -10x + 10
-4y = -10x - 6
-2y = -5x - 3
5x + 2y = 3