titik A(2,0,3), b(-3,1,n+2), dan c(m,2,1) segaris, nilai m-4n adalah

(-3,1,n+2) - (2,0,3) =
k(m, -2, -1) - (-3, 1, n+2)
(-5, 1, n-1) =
k(m+3, -3, n - 3)

1 = -3k
k = -1/3
-5 = k(m+3)
-5 = -1/3(m+3)
15=m+3
m = 15-3
m = 12

n-1 = k(n-3)
n-1 = -1/3(n-3)
3n - 3 = -(n-3)
3n - 3 = -n + 3
3n+n = 3+3
4n = 6
n = 6/4
n = 3/2

m-4n = 12 - 4(3/2) = 12 - 6 = 6