Setarakan persamaan reaksi berikut 1.CaCo3(s)+Hcl(aq)->CaCl2(aq)+Co2(g)+H2o(l) 2.NH3(g)+o2(g)->No(g)+H2o(g) 3.Ba(oH)2(aq)+p2o5(s)->Ba3(po4)2(s)+H2o(l)

Materi : Penyetaraan Reaksi
Kelas : 10

(1) CaCO3 + 2 HCl ==> CaCl2 + CO2 + H2O
misal :
a CaCO3 + b HCl ==> c CaCl2 + d CO2 + e H2O
Ca ==> a = c
C ===> a = d
Cl ===> b = 2c
O ===> 3a = 2d + e
H ===> b = 2e
asumsikan a = 1 , maka :
a = c = d = 1
b = 2c = 2(1) = 2
b = 2e <==> e = b/2 = 1

maka :
CaCO3 + 2 HCl ==> CaCl2 + CO2 + H2O


(2) 2 NH3 + 2 ½ O2 ==> 2 NO + 3 H2O
misal :
a NH3 + b O2 ==> c NO + d H2O
N ==> a = c
O ==> 2b = c + d
H ==> 3a = 2d
asumsikan a = 2, maka :
a = c = 2
3a = 2d <=> d = ౩/2 (a) = 3
2b = c + d = 2 + 3 = 5 <=> b = 2 ½

maka :
2 NH3 + 2 ½ O2 ==> 2 NO + 3 H2O

(3) 3 Ba(OH)2 + 2 P2O5 ==> Ba3(PO4)2 + 3 H2O
a Ba(OH)2 + b P2O5 ==> c Ba3(PO4)2 + d H2O
Ba ==> a = 3c
P ==> 2b = 2c
O ==> 2a + 5b = 8c + d
H ==> 2a = 2d
asumsikan a = 3, maka :
a = 3c <=> c = a/3 = 3/3 = 1
b = c = 1
a = d = 3

maka :
3 Ba(OH)2 + P2O5 ==> Ba3(PO4)2 + 3 H2O