diketahui titik A=(-1,5,4) B=(2,-1,-2) C=(3,p,q) jika titik A.B.C segaris maka nilai p dan q berturut turut = ....

AC = k AB
c-a = k b-a
(3,p,q)-(-1,5,4) = k (2,-1,-2)-(-1,5,4)
(4,p-5,q-4) = k (3,-6,-5)
4 = k.3
k = 4/3

p-5 = k.-6
p-5 = 4/3.-6
p-5 = -8
p = -3

q-4 = k.-5
q-4 = 4/3.-5
q-4 = -20/3
q = -20/3 + 4
q= -20/3 + 12/3
q= -8/3