Koordinat titik pusat lingkaran x2+y2-8x+10y+25=0 adalh

diketahui :
A = -8
B = 10
ditanya : p(a,b)
jawab :
a = -A/2
a =- (-8)/2
a = 4

b = -B/2
b = -10/2
b = -5

jadi pusat (4, -5)