tolong pake cara ya, makasih

nilai fungsi trigonometri

tan π/6 = 1/√3 --> tan² π/6 -  (1/√3)² = 1/3
sec π/4 = 1/(cos π/4) = 1/ (¹/₂ √2)= 2/√2 --> sec² π/4 = (2 /√2)²= 4/2 = 2
cosec 5π/6 = 1/(sin 5π/6) = 1/(1/2) =2 --> csc² 5π/6 = 2² = 4

tan² π/6 + sec² π/4 + cosec 5π/6 = (1/3 + 2 + 4) = 6¹/₃