f(x)=x^5-4x^3+3.dibagi dengan x^2-2x-3.Tentukan sisa dan hasil bagi dari pembagian suku banyak di atas

bisa horner ato misal dg bersusun
(x^5 + 0  - 4x³ + 0 + 3)/(x²-2x-3)= x³+2x²+3x+12
 x^5-2x^4-3x³
------------------- -
.......2x^4-x³ + 0 + 3 
.......2x^4-4x³-6x²
------------------------ -
...............3x³+6x²+0+3
...............3x³-6x²-9x
------------------------------- -
.....................12x²+9x+3
.....................12x²-24x-36
------------------------------------ -
............................33x+39
maka
h(x) = x³ + 2x² + 3x + 12
sisa = 33x + 39

x^2 - 2x - 3 = (x - 3)(x + 1) => x = 3 atau x = -1
f(x) = x^5 - 4x^3 + 3
3 | 1 ... 0 ... -4 ... 0 ... 0 .... 3
... | ...... 3 ... 9 ... 15 ... 45 ... 135
------------------------------------------ +
-1 | 1 ... 3 ... 5 .... 15 ... 45 | 138 => S1
... | ..... -1 ... -2 ... -3 ... -12
--------------------------------- +
.... 1 .... 2 .... 3 ... 12 | 33 => S2
Hasil bagi (x^3 + 2x^2 + 3x + 12)

Sisa = S2(x - 3) + S1
= 33 (x - 3) + 138
= 33x - 99 + 138
= 33x + 39