Jika diketahui massa atom relatif (Ar) Fe=56,C=12,dan O=16,maka Massa molekul relatif (Mr) Fe2(CO3)3 adalah...

Mr Fe2(CO3)3
= 2(Ar Fe) + 3{(Ar C) + 3(Ar O)}
= 2(Ar Fe) + 3(Ar C) + 9(Ar O)
= 2(56) + 3(12) + 9(16)
= 112 + 36 + 144
= 148 +
= 292

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MrFe2(CO3)3
Jawab:
2×ArFe + 3×ArC + 9×ArO
2×56 + 3×12 + 9×16
112+36+144
292gr/mol