diketahui suku banyak f(x)=x^4+2x^3-6x^2+px+8 jika f (-3)=2 maka p=.....

Masukkan (-3) ke persamaan awal
f(-3)= (-3)^4 + 2(-3)^3 - 6(-3)^2 + p(-3) + 8
= 81-54-54-3p+8
Karena f(-3) = 2 jadi,
81-54-54-3p+8= 2
-19-3p= 2
-3p= 2+19
-3p= 21
p = -7
Jadi nilai p = -7