misalkan a = [tex] \frac{1}{2} [/tex] dan b = [tex] \frac{1}{3} [/tex] , jika x = [tex]} (a - b)^{2} [/tex] maka... a. a < x b. b < x c. b < a d. [tex] x^{2} \
Matematika
anesadhityo7
Pertanyaan
misalkan a = [tex] \frac{1}{2} [/tex] dan b = [tex] \frac{1}{3} [/tex] , jika x = [tex]} (a - b)^{2} [/tex] maka...
a. a < x
b. b < x
c. b < a
d. [tex] x^{2} \ \textless \ a^{2} [/tex]
e. [tex] a^{2} \ \textless \ x^{2} [/tex]
a. a < x
b. b < x
c. b < a
d. [tex] x^{2} \ \textless \ a^{2} [/tex]
e. [tex] a^{2} \ \textless \ x^{2} [/tex]
1 Jawaban
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1. Jawaban Syubbana
a = 1/2
b = 1/3
x = (a-b)^2
= (1/2 - 1/3)^2
= (1/6)^2
= 1/36
x^2 = (1/36)^2
jawaban yg bnr adalah d
x^2 < a^2