jika f(x)=4x²-3x+2 nilai f'(1) =

f (x) = 4x² - 3x + 2

f'(x) = (4) (2) x²⁻¹ - 3
f'(x) = 8x - 3

Nilai f'(1)
= 8x - 3
= 8 (1) - 3
= 5

Turunan : [tex] x^{a} = ax^{a-1} [/tex]
a. [tex]4 x^{2} [/tex] = [tex]2.4 x^{2-1} [/tex] = 8x
b. [tex]1(-3) x^{1-1} [/tex] = - 3

f'(x) = 8x - 3
f'(1) = 8(1) - 3
f'(1) = 5