Kimia

Pertanyaan

Harga Ph larutan NH3 0,1 M (Kb = 1,0 x 10^-5) adalah

1 Jawaban

  • NH3 = 0,1 M
    Kb = 10^-5

    [OH-] = √ Kb × Mb
    = √ 10^-5 × 10^-1
    = √ 10^-6
    = 10^-3

    pOH = -log OH-
    =-log 10^-3
    = 3

    pH = 14 - 3
    pH = 11

Pertanyaan Lainnya