Jika x=2y,y=3z dan xyz =3888,maka
Matematika
hadimandala886
Pertanyaan
Jika x=2y,y=3z dan xyz =3888,maka
1 Jawaban
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1. Jawaban dikisiswanto
x = 2y = 6z
y = 3z
z = z
xyz = 3888
6z × 3z × z = 3.888
18z³ = 3.888
z³ = 216
z = ³√216
z = 6
maka
x = 6z = 36
y = 3z = 18
z = 6