Fungsi f(x) = -4 sin 3(x - phi/2) + 1 mempunyai nilai maksimum a dan nilai minimum b. Nilai (a - b)^2

Nilai maksimum / minimum fgngsi trigonometri

f(x)= - 4 sin 3(x-π/2) + 1
sin 3(x-π/2) = 1 --> f(x)= - 4(1) + 1  = -3
sin 3(x -π/2) = -1 --> f(x) = -4(-1)+ 1 = 6
a = 6 , b = - 3
nilai (a-b)² = (6 -(-3))² = (6+3)² = 9² = 81