dik fungsi f(x) = x³ dan g(x) = 4x + 2. Nilai X jika (g¯¹ o f¯¹ ) (x) = 2 adalah...

(g-¹of-¹)(x) = (fog)-¹(x)
mak
nilai (fog)(x) = (4x+2)³

y = (4x+2)³
y^⅓ = 4x + 2
4x = y^⅓ - 2
x = ¼y^⅓ - 2
(fog)-¹(x)= ¼x^⅓ - 2

jika (g¯¹ o f¯¹ ) (x) = 2
maka
2 = ¼x^⅓ - 2
¼x^⅓ = 2+2
¼x^⅓ = 4
x^⅓ = 16
x= (16)^⅓
x = (2⁴)^⅓
x = 2^4/3