Matematika

Pertanyaan

3p+4q-5r=-2 | 4p-2q-3r=12 | p+5q+2r=3. ditanya p,q dan r ?

1 Jawaban

  • diketahui:
    3p+4q-5r = -2 (persamaan 1)
    4p-2q-3r = 12 (persamaan 2)
    p+5q+2r = 3 (persamaan 3)

    ditanya:
    p, q, r =?

    jawab:
    eliminasi persamaan 1 dan 3
    3p+4q-5r = -2 | ×1
    p+5q+2r = 3 | ×3
    ---------------------------
    3p+4q-5r = -2
    3p+15q+6r = 9
    ----------------------- -
    -11q-11r = -11
    -q-r = -11
    q+r = 11 (persamaan 4)

    eliminasi persamaan 2 dan 3
    4p-2q-3r = 12 | ×1
    p+5q+2r = 3 | ×4
    ----------------------------
    4p-2q-3r = 12
    4p+20q+8r = 12
    ------------------------- -
    -22q-11r = 0
    -2q-r = 0
    -2q = r

    nilai r disubstitusi ke perasamaan 4
    q+r = 11
    q + (-2q) = 11
    -q = 11
    q = -11

    nilai q disubstitusi ke persamaan 4
    q+r = 11
    -11 + r = 11
    r = 11 + 11
    = 22

    substitusi persamaan 3
    p+5q+2r = 3
    p + 5×(-11) + 2 × 22 = 3
    p - 55 + 44 = 3
    p - 11 = 3
    p = 3+11
    = 14

    jadi nilai p = 14, q = -11, dan r = 22

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