8 sin π/4 cos 3/4 + cos²π./6-sin²3/4π
Matematika
Verdiardiansah111
Pertanyaan
8 sin π/4 cos 3/4 + cos²π./6-sin²3/4π
2 Jawaban
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1. Jawaban fadhildzikry
akar = {
pangkat = ^
8 . sin 180/4 . cos 3/4 . 180 + cos^2 180/6 -sin^2 3/4 . 180
8 sin 45 . cos 135 + cos^2 30 . -sin^2 135
8.1/2 {2 . -cos 45 + (1/2 {3)^2 . -sin^2 45
4 {2 . -1/2 {2 + 3/4 . -(1/2 {2)^2
-4 + 3/4 . -1/2
-4 + (-3/8)
-32/8 - 3/8
-35/8 -
2. Jawaban arsetpopeye
8 sin π/4 cos 3π/4 + cos^2 π/6 - sin^2 3π/4
= 8 sin 45° cos 135° + (cos 30°)^2 - (sin 135°)^2
= 8 . 1/2 √2 . -1/2 √2 + (1/2 √3)^2 - (1/2 √2)^2
= -4 + 3/4 - 2/4
= (-16 + 3 - 2)/4
= -15/4
= -3 3/4