Matematika

Pertanyaan

x+1
²log ²log(2 +3)=1+²logx
x+1 ²log ²log(2     +3)=1+²logx

2 Jawaban

  • ^ tanda pangkat
    ²log ²log (2^(x+1) + 3) = ²log 2 + ²log x
    ²log ²log (2^(x+1) + 3) = ²log 2x
    ²log (2^(x+1) + 3) = 2x
    2^2x = 2^(x+1) + 3
    (2^x)^2 = 2^x.2^1 + 3
    (2^x)^2 = 2^x.2 + 3
    misal 2^x = p
    p^2 = p.2 + 3
    p^2 = 2p + 3
    p² - 2p - 3 = 0
    (p + 1)(p - 3) = 0
    p + 1 = 0
    p = -1
    kembalikan p = 2^x
    2^x = -1 (tidak memenuhi pangkat tidak ada negatif hasilnya )
    p - 3 = 0
    p = 3
    2^x = 3
    x = ²log 3
  • Bab Logaritma
    Matematika SMA Kelas X

    ²log ²log (2^(x + 1) + 3) = 1 + ²log x
    ²log ²log (2^x . 2+ 3) = ²log 2 + ²log x
    ²log (2 . 2^x + 3) = 2x
    2 . 2^x + 3 = 2^2x
    2^2x - 2 . 2^x - 3 = 0
    (2^x - 3) (2^x + 1) = 0
    2^x = 3
    ²log 3 = x
    x = log 3 / log 2
    x = 1,58


    atau

    2^x + 1 = 0
    2^x = -1 (tidak memenuhi)

    jadi, x = 1,58

    x + 1 = 1,58 + 1 = 2,58