jika f : R -> R,g : R -> R dengan f(x)=3x+1 dan g(x)=2xpangkat2-5x+1, maka nilai dari (f-g)(-2)=..

(f-g)(x)
=> f(x) - g(x)
=> 3x + 1 - (2x^2 - 5x + 1)
=> -2x^2 + 8x

(f-g)(x) = -2x^2 + 8x
(f-g)(-2) = -2 × (-2)^2 + 8×(-2)
(f-g)(-2) = -2 × 4 - 16
(f-g)(-2) = -8-16
(f-g)(-2) = -24