tolong dong caranya gimna?

Dik : PR = 12cm
PQ = 9cm

Berarti,
RQ^2 = RP^2 + PQ^2
= 12^2 + 9^2
RQ = 15cm

RQ = d, maka r = 7,5cm

Lj. = 180 / 360 x 3,14 x 7,5 x 7,5
= 1/2 x 176,625
= 88,3125 cm^2

L segitiga = a x t / 2
= 9 x 12 / 2
= 54 cm^2

L arsir = 88,3125 - 54
= 34,3125cm^2

Sekian.

Pembahasan.

L diarsir = L ½ lingkaran - L ∆

Kita hitung luas ½ O

Gunakan teorema Phytagoras

x² = 9² + 12²
x² = 81 + 144
x² = 225
x = 15

x masih diameter , maka jari jarinya 7,5

π ≈ 3,14

L½O = ½ × π × 7,5²
L½O = ½ × 3,14 × 56,25
L½O = 88,3125

kita hitung luas ∆ nya

L∆ = ½.a.t
L∆ = ½.9.12
L∆ = 9.6
L∆ = 54

L diarsir = 88,3125 - 54
L diarsir = 34,3125 cm²

Opsi A