Integral akar dri 1+ √x dx

int x√(x+1) dx
misal, u = x + 1 --------> x = u - 1
du = dx
shg, integral di atas dapat menjadi :
int (u-1) √u du
= int (u - 1) u^(1/2) du
= int (u^(3/2) - u^1/2) du
= 2/5 u^(5/2) - 2/3 u^(3/2) + C
= 2/5 (x+1)^(5/2) - 2/3 (x+1)^(3/2) + C

Semoga membantu

int. 1 + √x = int. 1 + x^½
= x + 2/3 x^(3/2)


int. = integral