tolong dong bantuin aku ngerjain pr matematika no 38,40 diutamakan caranya yah..jawab secepatnya

nmr 38 caranya gini. tapi nmr 40 gatau

40. ∫4/√(2x+1) dx = ∫4(2x+1)^(1/2) dx

misal
u = 2x + 1
du = 2 dx
dx = 1/2 du

∫4(2x+1)^(1/2) dx
(1/2) x ∫4U^(1/2) du
(1/2) x 4∫U^(1/2) du
2 ∫U^(1/2) du
2 x 1/(1-(1/2) U^(1-(1/2) + c
2 x 2 x U^(1/2) + c
4U^(1/2) + c
4(2x + 1)^(1/2) + c

4√(2x+1) + c